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Sonam Singh

  string input = @"cool  man dog no dude yes fight son";
  string pattern = @"cool (?<hello>((.)* ))   (?<h>( (dude)?)) (?(h)(?<dude>((.)*)))";
       MatchCollection matches = Regex.Matches(input, pattern, RegexOptions.ExplicitCapture
              | RegexOptions.IgnorePatternWhitespace);

            foreach (Match match in matches)
                Console.WriteLine("dude=" + match.Groups["dude"].Value);
                Console.WriteLine("hello=" + match.Groups["hello"].Value);

hello=  man dog no dude yes fight son


But the required output is:


dude=yes fight son
hello=  man dog no


The target is that i want to capture "strings that have cool as first 'word'  and have 'dude' word as optional in between".
Now,I want string that follows word "cool" ("man dog no") until "dude" word comes or end comes.
if "dude" word comes,I want the string that follows word "dude".

Can anybody explain me why the output is not correct or where i am wrong?
Thanks in advance.

Posted on Thursday, December 24, 2009 7:05 AM .Net , Fun , C# | Back to top

Comments on this post: Capturing optional groups in regular expressions?

# re: Capturing optional groups in regular expressions?
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Hi Sonam,

may I suggest you the following Regex pattern:


This pattern matches such input text as:
1)@"cool man dog no dude yes fight son"; or
2)@"cool man dog no ";

In case 1) you have to extract the thirst and second groups
In case 2) it will be the 3rd group.

Hope this could help you.

Best regards.

Left by Larissa on Dec 25, 2009 5:40 AM

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