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@matchristian
• matchristian @nickgravelyn I always watch them hoping for a 'new XNA' which would make me buy one almost immediately. about 1 day ago
• matchristian Hour and a half of bball practice; nonstop shoot run dribble, repeat a lot. about 1 day ago
• matchristian "Ever seen River Monsters where the fish go after male genitalia?" No, Trigs cashier, I have not. #awkward about 3 days ago
• matchristian Filming fact: Sriracha is an acceptable form of fake blood, except now my arm smells like Chinese food. about 3 days ago
• matchristian The guy next to me is freaking out about how there's 'too much texting and email' now. You, good sir, are obsolete. about 5 days ago

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Code.Blog Code Talk for the Game Developer
We got our Calc 3 tests today and as we were being shown how to get the answers, we came across a problem the teacher said "I'm curious that so many people got this question, maybe they learned it in some other class."  I present to you the problem:

Recall that the angular momentum of a particle of mass m along a path R(t) is defined by the vector quantity L(t) = mR(t) x v(t).  Consider a point R(t0) = p on the planar curve R(t).  Call p a point of maximal angular momentum if it has the property that amongst all particles of unit mass and unit speed on curves passing through p, |L(t0)| is maximum.  Suppose that each point of R(t) is a point of maximal angular momentum.  What can we say about R(t)?  That is, what kind of path does R(t) have to be?

Needless to say I got the question quite wrong.... Posted on Friday, April 18, 2008 1:45 PM | Back to top

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